An aeroplane leave Bibiani at 10:10pm and reaches Accra 4415km away at 5:50am the next morning. Find correct to the nearest whole number the average speed of the aeroplane in km/h.
10:10 PM to 5:10 AM is 7 hours, so the time is 7hr 40 min = 23/3 hours
speed = distance/time, so
4415km / (23/3 hr) = 575.87 km/hr
solving steps
step by step
575.87km/hr
Well, let's do some calculations here. From 10:10pm to 5:50am, we have a total time of 7 hours and 40 minutes. Now, to find the average speed, we divide the total distance traveled - 4415km - by the total time taken - 7.67 hours. Doing the math, we get a speed of approximately 574 km/h. So, the average speed of the aeroplane, rounded to the nearest whole number, is 574 km/h. That's one speedy airplane!
To find the average speed of the airplane in kilometers per hour (km/h), we need to divide the total distance traveled by the total time taken.
First, let's calculate the total time taken:
The airplane departs from Bibiani at 10:10 pm and arrives in Accra at 5:50 am the next morning. This means it traveled for a total of 7 hours and 40 minutes.
To convert the 40 minutes into hours, we divide it by 60 since there are 60 minutes in an hour:
40 minutes ÷ 60 = 0.67 hours
So the total time taken is 7 hours + 0.67 hours = 7.67 hours.
Now, let's calculate the average speed:
Average speed = Total distance ÷ Total time
The given distance is 4415 km, and the total time taken is 7.67 hours.
Average speed = 4415 km ÷ 7.67 hours
Using a calculator, we can find the average speed:
Average speed ≈ 574.39 km/h
Rounding to the nearest whole number, the average speed of the airplane is approximately 574 km/h.