an object that weighs 3N displaces 90mL of water which weighs 2.8N. What is the buoyant force on the object? idk how to solve this problem PLEASE HELP!! thanks
To solve this problem, you need to understand the concept of buoyant force and Archimedes' principle.
Buoyant force is the upward force exerted by a fluid (in this case, water) on an object that is submerged or partially submerged in it. According to Archimedes' principle, the buoyant force on an object is equal to the weight of the fluid displaced by the object.
Here's how you can solve this problem step-by-step:
1. Determine the weight of the water displaced: In this case, the water displaced is 90 mL, and its weight is given as 2.8 N.
2. Find the weight of the object: The weight of the object is given as 3 N.
3. Calculate the difference in weights: Subtract the weight of the water displaced from the weight of the object. In this case, 3 N - 2.8 N = 0.2 N.
4. The resulting value (0.2 N) is the buoyant force acting on the object. The positive value indicates an upward force.
Therefore, the buoyant force on the object is 0.2 N.