In gas law calculations, air is often considered to be a single gas with a molar mass of 29 g/mole. On this basis, calculate the density of air, in g/L, on a hot summer day when the temperature is 41oC and the atmospheric pressure is 0.91 atm.

If there were one mole of air, it would occupy 28.3L under those conditions.

so, you must have 28.3/22.4 = 1.26 moles
That would be 1.26*29g/28.3L = 1.29 g/L