physics

A rock is thrown off a vertical cliff at an angle of 58.6o above horizontal. The cliff is 84.6 m high and the ground extends horizontally from the base. The initial speed of the rock is 21.8 m/s. Neglect air resistance.

To what maximum height, in meters, does the rock rise above the edge of the cliff?

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  1. vertical speed initial :(Vi): 21.8*sin58
    initial KE in vertical: 1/2 m (21.8*sin58)^2
    final change in potential energy:
    mgh=1/2 m (21.8*sin58)^2
    solve for height h above the upper edge of the cliff.

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    bobpursley
  2. ok i got! what about these questions:
    How high above the ground, in meters, is the rock 2.21 s before it hits the ground?
    How far horizontally from the cliff, in meters, is the rock 2.21 s before it hits the ground?

    using the same numbers given above

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