what would the dimensions of a retangle be whose perimeter is 50(P=50)inches when the length is 2x-5 ane the width is unknown
The width must be 25 - (2x-5) = 30-2x, since the sum of the length and width must be half the perimeter.
You do not have enough information to solve for x, or a specific length and width.
I beleive I have figured this one out:
2x+2(2x-5)=50
2x being twice the width
2(2x-5) being twice the length
and 50 being the perimeter
2x=2(2x-5)=50
2x+4x-10=50
6x-10 =50
6x=60
x=10 If you place 10 whwre the x is you get 50 as a result
If the width is x then you are correct. You had only stated that the length is 2x-5, and had not defined x. Your first line should have been
2x + 2x(2x-5) = 50
The rest is fine. The width is 10 and the length is 15
To find the dimensions of the rectangle, we need to solve for the width using the given information.
First, we can set up an equation using the formula for the perimeter of a rectangle, which is P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.
In this case, we are given that the perimeter is 50 inches, so we have the equation 50 = 2L + 2W.
However, we only know the expression for the length, which is 2x-5. To find the width, we need another equation that relates the length and width.
The information provided states that the sum of the length and width must be half the perimeter. Using this information, we can set up another equation:
(2x-5) + W = 25
Simplifying this equation gives:
2x + W = 30
Now we have a system of two equations:
50 = 2L + 2W
2x + W = 30
To solve this system, we can use substitution or elimination. Let's use substitution.
From the second equation, we can rewrite it as W = 30 - 2x.
Substituting this expression for W in the first equation gives:
50 = 2L + 2(30 - 2x)
50 = 2L + 60 - 4x
-10 = 2L - 4x
-5 = L - 2x
Now we have another equation relating L and x.
We have a system of two equations:
-5 = L - 2x
-10 = 2L - 4x
To find the dimensions of the rectangle, we need to solve this system of equations. However, we cannot determine the specific values for L and W because we don't have enough information.
If you have additional information or constraints for the values of L or x, we can proceed with solving the system. Otherwise, we can only conclude that the dimensions of the rectangle cannot be determined with the given information.