what would the dimensions of a retangle be whose perimeter is 50(P=50)inches when the length is 2x-5 ane the width is unknown
The width must be 25 - (2x-5) = 30-2x, since the sum of the length and width must be half the perimeter.
You do not have enough information to solve for x, or a specific length and width.
I beleive I have figured this one out:
2x being twice the width
2(2x-5) being twice the length
and 50 being the perimeter
x=10 If you place 10 whwre the x is you get 50 as a result
If the width is x then you are correct. You had only stated that the length is 2x-5, and had not defined x. Your first line should have been
2x + 2x(2x-5) = 50
The rest is fine. The width is 10 and the length is 15