Find the number of 12 lb bags of fertilizer and 15 lb. bags of feed in yesterday’s delivery if there were 6 more bags of feed than bags of fertilizer, and the total delivery weighed 333lb.
I got x=14 and x+6= 20. But that does not seem correct.
To solve this problem, we need to set up a system of equations based on the given information.
Let's assume the number of 12 lb bags of fertilizer is x, and the number of 15 lb bags of feed is y.
From the given information, we know that there were 6 more bags of feed than bags of fertilizer, so we can write the equation: y = x + 6.
We also know that the total delivery weighed 333 lb, so we can write another equation: 12x + 15y = 333.
Now we have a system of two equations that we can solve simultaneously to find the values of x and y.
Substitute the value of y from the first equation into the second equation:
12x + 15(x + 6) = 333.
12x + 15x + 90 = 333.
27x = 333 - 90.
27x = 243.
x = 243 / 27.
x = 9.
Now substitute the value of x into the first equation to find y:
y = 9 + 6.
y = 15.
Therefore, there were 9 bags of 12 lb fertilizer and 15 bags of 15 lb feed in yesterday’s delivery.
So, your initial calculation of x=14 and x+6= 20 is not correct. The correct solution is x=9 and y=15.
what do you mean, it does not "seem" correct? Did you not check it?
In fact, since both of your answers are even, there is no way the weights could add up to an odd number.
And, to add insult to injury, you declined even to show your work.
So, if there were x 12-lb bags, you know that
12x + 15(x+6) = 333
x = 9