Eugene can read 11 1/2 pages of reading vook everyday.how many pages would she have read in 5 days

11 1/2*5= 23/2 *5 (because 2 times 11 plus 1 is 23, and that is over 2), which equals 115/2, which in turn equals 57.5. Eugene would have read 57.5 pages in 5 days.

To determine the number of pages Eugene would have read in 5 days, you need to multiply the number of pages she can read in one day (11 1/2) by the number of days (5).

First, let's convert the mixed number 11 1/2 to an improper fraction:
11 1/2 = (11 * 2 + 1) / 2 = 23/2

Now multiply the improper fraction by 5:
(23/2) * 5 = (23 * 5) / 2 = 115/2

Thus, Eugene would have read 115/2 pages in 5 days. To simplify this fraction, you can divide the numerator and denominator by their greatest common divisor, which is 5:
(115/2) ÷ 5 = (115 ÷ 5) / (2 ÷ 5) = 23/1

Therefore, Eugene would have read 23 pages in 5 days.

Also, if possible, could you read my question and answer it? It's in the newest section...……………..