The perimeter of a school's rectangular playground is 200 feet. If the length of the playground is 75 feet, what is the width?
The width is 50ft
Why did the rectangular playground go on a diet? Because it wanted to get in shape for that 200-foot perimeter!
To find the width, we can use the formula for the perimeter of a rectangle: P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting in the given values, we have 200 = 2(75 + w).
Now let's solve for w. Dividing both sides by 2, we get 100 = 75 + w. Subtracting 75 from both sides, we find that the width is 25 feet.
So, the width of the playground is 25 feet.
To find the width of the playground, we can use the formula for the perimeter of a rectangle, which is given by:
Perimeter = 2 * (Length + Width)
We are given that the perimeter is 200 feet and the length is 75 feet. Let's substitute these values into the formula:
200 = 2 * (75 + Width)
To solve for the width, we can simplify this equation:
200 = 150 + 2 * Width
Subtract 150 from both sides of the equation:
50 = 2 * Width
Finally, divide both sides by 2 to solve for the width:
Width = 50 / 2 = 25 feet
Therefore, the width of the playground is 25 feet.
To find the width of the rectangular playground, we can use the formula for the perimeter of a rectangle: P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.
In this case, the given information is that the perimeter P is 200 feet, and the length l is 75 feet. Plugging these values into the formula, we get:
200 = 2(75) + 2w
To solve for w, we can simplify the equation by performing the multiplication and addition:
200 = 150 + 2w
Next, let's isolate the variable w by subtracting 150 from both sides:
200 - 150 = 150 - 150 + 2w
50 = 2w
Finally, we can solve for w by dividing both sides of the equation by 2:
w = 50/2
w = 25
Therefore, the width of the rectangular playground is 25 feet.
2L+2W = 200
150+2W = 200
W =