On a farm there are some cows and some chickens. If there is a total of 40 heads and 112 legs. How many cows are there?
try using some type of algebra and use the fact that cows have 4 legs and chickens have 2. the rest of the stage is urs!
sorry i couldn't help
but i did my best
bc im still too little to help
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u probs already got the answer lol
I don;t care I want answers!!!!!1 losers! hiding the answers!
To determine the number of cows on the farm, we can set up a system of equations based on the given information. Let's use 'c' to represent the number of cows and 'ch' to represent the number of chickens.
Each cow has one head and four legs, so the total number of cow heads is equal to the number of cows:
c = number of cows
Each chicken has one head and two legs, so the total number of chicken heads is equal to the number of chickens:
ch = number of chickens
Given that there is a total of 40 heads on the farm, we can write the first equation as:
c + ch = 40
Given that there is a total of 112 legs on the farm, we can write the second equation as:
4c + 2ch = 112
Now, we have a system of two equations:
c + ch = 40
4c + 2ch = 112
To solve this system, we can use substitution or elimination method. Let's use the elimination method:
Multiplying the first equation by 2, we get:
2c + 2ch = 80
Subtracting the new first equation from the second equation, we eliminate 'ch':
(4c + 2ch) - (2c + 2ch) = 112 - 80
2c = 32
Dividing both sides of the equation by 2, we find:
c = 16
Therefore, there are 16 cows on the farm.