An evacuated flask weighed 30.50g when filled with dry hydrogen and 39.82gs when filled with dry chlorine at s.t.p when emptied the flask weights 30.23.calculate the RMM of chlorine?
mass H2 = 30.50 - 30.23 = 0.27 g......RMM H2 = 2.0
mass Cl2 = 39.82 - 30,23 = 9.59........RMM Cl2 = ?
Use proportion.
(mass H2/mass Cl2) = (RMM H2/RMM Cl2)
(0.27/9.59) = (2/x)
x = 2*9.59/0.27 = 71.0
To find the relative molecular mass (RMM) of chlorine, we need to calculate the mass difference.
Step 1: Calculate the mass of hydrogen gas.
The mass of the hydrogen gas can be found by subtracting the weight of the evacuated flask (30.50 g) from the weight of the filled flask (30.82 g):
Mass of hydrogen = 39.82 g - 30.50 g = 9.32 g
Step 2: Calculate the mass of chlorine gas.
The mass of the chlorine gas can be found by subtracting the weight of the evacuated flask (30.50 g) from the weight of the emptied flask (30.23 g):
Mass of chlorine = 30.50 g - 30.23 g = 0.27 g
Step 3: Calculate the number of moles of each gas.
To calculate the number of moles, divide the mass of each gas by their respective molar masses. The molar mass of hydrogen (H₂) is 2 g/mol and the molar mass of chlorine (Cl₂) is unknown (which we want to find):
Moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen
Moles of hydrogen = 9.32 g / 2 g/mol = 4.66 mol
Moles of chlorine = Mass of chlorine / Molar mass of chlorine
Moles of chlorine = 0.27 g / Molar mass of chlorine
Step 4: Express the ratio of moles between hydrogen and chlorine.
Since chlorine and hydrogen combine in a 1:1 molar ratio to form hydrogen chloride (HCl), the ratio of moles between hydrogen and chlorine is 1:1.
Moles of hydrogen = Moles of chlorine
4.66 mol = 0.27 g / Molar mass of chlorine
Step 5: Solve for the molar mass of chlorine.
To find the molar mass of chlorine, rearrange the equation:
Molar mass of chlorine = 0.27 g / 4.66 mol
Molar mass of chlorine = 0.057976 g/mol
Therefore, the relative molecular mass (RMM) of chlorine is approximately 0.058 g/mol.
To calculate the relative molecular mass (RMM) of chlorine, we need to use the given information about the flask and the weights of hydrogen and chlorine.
Step 1: Find the weight of the hydrogen gas in the flask.
The initial weight of the flask with hydrogen is 30.50g, and the weight of the empty flask is 30.23g. Therefore, the weight of the hydrogen gas in the flask is the difference between the two: 30.50g - 30.23g = 0.27g.
Step 2: Find the weight of the chlorine gas in the flask.
The weight of the chlorine-filled flask is 39.82g. Since the weight of the empty flask is 30.23g, the weight of the chlorine gas in the flask is: 39.82g - 30.23g = 9.59g.
Step 3: Calculate the ratio of the weights of chlorine and hydrogen.
The ratio of the weights of chlorine to hydrogen is given by:
(Weight of chlorine) / (Weight of hydrogen) = 9.59g / 0.27g = 35.52.
Step 4: Determine the relative atomic mass (RAM) of hydrogen.
The RAM of hydrogen is 1g/mol.
Step 5: Calculate the RMM of chlorine.
The RMM of chlorine is calculated by multiplying the ratio obtained in Step 3 by the RAM of hydrogen:
RMM = (Ratio of weights) * (RAM of hydrogen) = 35.52 * 1 = 35.52g/mol.
Therefore, the RMM of chlorine is 35.52g/mol.