Enter your answer and show all the steps that you use to solve this problem in the space provided.

Day Sunday Monday Tuesday Wednesday Thursday Friday Saturday
Temperature (degrees F) 49 55 52 46 47 42 38

Julia measured the high temperature in her town for one week. Using the chart above, find the mean absolute deviation for the high temperatures. Round your answer to the nearest tenth.

Be sure to show your work for finding:

the mean of the set of data
the distance of each number from the mean
the mean absolute deviation

To find the mean absolute deviation for the high temperatures, we need to follow these steps:

1. Find the mean (average) of the set of data.
2. Calculate the distance of each number from the mean.
3. Find the mean (average) of these distances to get the mean absolute deviation.

Let's go through each step:

Step 1: Find the mean (average) of the set of data.

To find the mean (average), we add up all the values and divide the sum by the total number of values.

The temperatures for the week are:
49, 55, 52, 46, 47, 42, 38

Add them up:
49 + 55 + 52 + 46 + 47 + 42 + 38 = 329

Divide by the total number of values, which is 7 (since we have temperatures for 7 days):
Mean = 329 / 7 = 47

So, the mean (average) temperature is 47 degrees Fahrenheit.

Step 2: Calculate the distance of each number from the mean.

To calculate the distance of each number from the mean, we subtract the mean from each individual temperature value.

The temperatures are:
49, 55, 52, 46, 47, 42, 38

Distance from mean:
|49 - 47| = 2
|55 - 47| = 8
|52 - 47| = 5
|46 - 47| = 1
|47 - 47| = 0
|42 - 47| = 5
|38 - 47| = 9

Step 3: Find the mean (average) of these distances to get the mean absolute deviation.

To find the mean (average) of the distances, we add up all the distances and divide the sum by the total number of distances.

Distances:
2, 8, 5, 1, 0, 5, 9

Add them up:
2 + 8 + 5 + 1 + 0 + 5 + 9 = 30

Divide by the total number of distances, which is 7:
Mean absolute deviation = 30 / 7 ≈ 4.3

Therefore, the mean absolute deviation for the high temperatures, rounded to the nearest tenth, is approximately 4.3 degrees Fahrenheit.

the mean is 47

now figure the differences from 47 for each value: 2,8,5, ...
take the mean of their absolute values

Questions

mathematics
Enter your answer and show all the steps that you use to solve this problem in the space provided.
Day Sunday Monday Tuesday Wednesday Thursday Friday Saturday
Temperature (degrees F) 49 55 52 46 47 42 38

Julia measured the high temperature in her town for one week. Using the chart above, find the mean absolute deviation for the high temperatures. Round your answer to the nearest tenth.

Be sure to show your work for finding:

the mean of the set of data
the distance of each number from the mean
the mean absolute deviation

marty
Oct 12, 2020
the mean is 47
now figure the differences from 47 for each value: 2,8,5, ...
take the mean of their absolute values

👨‍🏫
oobleck
Oct 12, 2020
I DON;T know

Nyla
today at 9:05am


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