Hannah and Corrine are playing a game by rolling two cubes, each numbered 1 through 6. If the sum of the numbers on the cubes is 7, Hannah wins. If the sum is not 7, Corrine wins.Which best explains if Corrine is correct?
No choices given, and what does throwing dice have to do with being correct?
To determine if Corrine is correct, we need to look at the possible outcomes of rolling two cubes and calculate the probability of their sum equaling 7.
When rolling two cubes, we have a total of 6 x 6 = 36 possible outcomes, as each cube has 6 sides numbered from 1 to 6.
Now let's list down all the possible combinations of numbers that sum up to 7:
1 + 6 = 7
2 + 5 = 7
3 + 4 = 7
4 + 3 = 7
5 + 2 = 7
6 + 1 = 7
We have a total of 6 combinations that result in a sum of 7.
Therefore, the probability of the sum of the numbers on the cubes equaling 7 is 6/36 or 1/6.
Since there is a probability of 1/6 for the sum to be 7, and a 5/6 chance for the sum to be anything other than 7, Corrine is indeed correct.
To determine whether Corrine is correct, we need to analyze the probability of rolling two dice and obtaining a sum of 7.
First, let's calculate the total number of possible outcomes when rolling two dice. Each dice has 6 possible outcomes (numbered from 1 to 6), so the total number of outcomes for both dice is 6 * 6 = 36.
Next, let's determine the number of outcomes that result in a sum of 7. To do this, we can list all the possible combinations that equal 7:
- (1, 6)
- (2, 5)
- (3, 4)
- (4, 3)
- (5, 2)
- (6, 1)
Counting all these combinations, we have a total of 6 outcomes that sum up to 7.
Therefore, the probability of rolling a sum of 7 is 6/36, which can be simplified to 1/6.
Since there are 6 possible outcomes that lead to a win for Hannah (sum of 7) and 36 total possible outcomes, the probability of Hannah winning is 6/36, which can also be simplified to 1/6.
Based on this analysis, both Hannah and Corrine have an equal probability of winning. Therefore, Corrine is correct.