A blue and a green billiard ball, each with a mass of 0.15 kg, collide directly. Before the collision, the blue ball had a speed of 3 m/s while the green ball had a speed of 2 m/s. After the collision, the green ball stays in place while the blue ball continues in motion.

In 3-4 sentences, represent the situation before and after the collision and calculate the speed of the blue ball after the collision.

Before the collision, the blue ball was moving at 3 m/s and the green ball was moving at 2 m/s. After the collision, the green ball stayed in place while the blue ball continued in motion. Using the conservation of momentum, the speed of the blue ball after the collision can be calculated as 4 m/s.

Before the collision, the blue ball is moving with a velocity of 3 m/s to the right, while the green ball is stationary. After the collision, the green ball stays in place and the blue ball continues in motion. To calculate the speed of the blue ball after the collision, we can use the law of conservation of momentum. The initial momentum of the system is equal to the final momentum, so we have (0.15 kg)(3 m/s) = (0.15 kg + 0.15 kg) * v_blue, where v_blue is the velocity of the blue ball after the collision. Simplifying this equation gives v_blue = 1.5 m/s. Therefore, the speed of the blue ball after the collision is 1.5 m/s.

In the situation before the collision, the blue ball is moving with a speed of 3 m/s, while the green ball is moving with a speed of 2 m/s in the opposite direction. After the collision, the green ball comes to a stop and stays in place, while the blue ball continues its motion. To calculate the speed of the blue ball after the collision, we can use the law of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision. Since the green ball comes to a stop, the momentum of the blue ball after the collision will be equal to its initial momentum, which can be calculated using the equation: momentum = mass x velocity.