I've missed quite alot of school because I was sick and when I get back I have a test right away. The only problem is I have a worksheet and no answers, I really would appreciate help! I can't tell if I'm in the right direction or not for this test! Thank you!!

1. 3(x-5)-2(3x+1)+14=5(1-x)+3(x-12)-x
2. (x-1)^2 + (2-x)(x+2)+3=(x+2)^2-x^2+3x-5
3. (x+3)^2-(x-1)(1+x)+1=x^2+x+7-(x-2)^2
4. (1-x)^2-(2+x)(2-x)+4x=11(x^2-x)-(2-3x)^2+12
5. (2x-3)^2-(x+1)(1-x)+x=(3x-1)^2+(1-2x)(2x+1)-9
6. (2x-1)^2-(x+3)^2+x=(x+1)(1-x)+4(x^2-6x-1)
7. (3x-2)^2-(4+x)(x-4)+3x=(1-2x)^2+4(x^2-2x+3)+19

Thank you~

I do not know if you are supposed to combine terms or solve for x.

The first problem can be rewritten
3x - 15 -6x -2 + 14
= 5 - 5x + 3x -36 - x
Now combine terms
-3x -3 = -3x -31
This is an impossibility since it leads to -3 = -31.
The original statement cannot be correct.

3-3

To solve each of these equations, we will start by simplifying both sides of the equation and combining like terms. Then we will solve for the unknown variable 'x'.

Let's take the first equation as an example and walk through the process step by step:

1. 3(x-5) - 2(3x+1) + 14 = 5(1-x) + 3(x-12) - x

First, we'll perform the distribution and multiplication on each side:

3x - 15 - 6x - 2 + 14 = 5 - 5x + 3x - 36 - x

Next, we'll combine like terms on each side:

-3x - 3 = -33 - 3x

Now, we can see that both sides of the equation have '-3x' terms. We can subtract '-3x' from both sides to simplify further:

-3 = -33

Since -3 is not equal to -33, we have a contradiction. Therefore, this equation has no solution.

Now, you can follow the same process for each of the remaining equations to solve them. Remember to simplify both sides, combine like terms, and isolate the variable 'x'.