A 10-volt battery is connected to a circuit with two resistors, R1 and R2, in parallel. If R1 is greater than R2, what does Kirchhoff's loop rule indicate about the voltage drops across the resistors?
The voltage drops across both R1 and R2 will be 5 V each.
The voltage drops across both R1 and R2 will be 10 V each.
The voltage drop across R1 will be less than the voltage drop across R2.***
The voltage drop across R1 will be greater than the voltage drop across R2.
The voltage drops across both R1 and R2 will be 10 V each.
Well, Kirchhoff's loop rule indicates that the voltage drop across each resistor in a parallel circuit is the same. So, if R1 is greater than R2, the voltage drop across R1 will be the same as the voltage drop across R2. In other words, they will both get an equal share of the 10 volts from the battery. So, the correct answer is that the voltage drops across both R1 and R2 will be 10 V each.
The correct answer is: The voltage drop across R1 will be greater than the voltage drop across R2.
To determine the voltage drops across the resistors in this circuit, we can use Kirchhoff's loop rule. Kirchhoff's loop rule states that the sum of the voltage drops around any closed loop in a circuit is equal to zero.
In this case, we have a 10-volt battery connected to two resistors, R1 and R2, in parallel. When resistors are connected in parallel, the voltage across each resistor is the same. Since the battery has a voltage of 10 volts, the voltage drops across both R1 and R2 will be the same.
Therefore, the correct answer is: The voltage drops across both R1 and R2 will be the same.