Three resistors are placed in series. They have the following resistances: R1 = 20 ohms, R2 = 20 ohms, R3 = 10 ohms. What current would be moved through this circuit by a 5-V power supply?
25A
250A
1.0A **
0.10A
To find the current flowing through the circuit, we can use Ohm's Law which states that the current (I) flowing through a circuit is equal to the voltage (V) across the circuit divided by the total resistance (R).
First, we need to calculate the total resistance (RT) in the circuit by summing the individual resistances (R1, R2, R3) since they are connected in series.
RT = R1 + R2 + R3 = 20 ohms + 20 ohms + 10 ohms = 50 ohms
Next, we can use Ohm's Law to calculate the current (I).
I = V / RT = 5 V / 50 ohms = 0.1 A
Therefore, the current flowing through the circuit by a 5-V power supply is 0.1A