What mass (in grams) of iron(III) oxide contains 58.7 g of iron?
58.7 g Fe x (molar mass Fe2O3/2*atomic mass Fe) = ? g Fe2O3
To find the mass of iron(III) oxide that contains 58.7 g of iron, we need to determine the molar mass of iron(III) oxide.
The chemical formula for iron(III) oxide is Fe2O3.
The molar mass of Fe2O3 can be calculated by summing the molar masses of all its constituent elements.
Molar mass of Fe = 55.845 g/mol.
Molar mass of O = 16.00 g/mol.
Fe2O3 contains 2 Fe atoms and 3 O atoms, so the molar mass of Fe2O3 can be calculated as follows:
Molar mass of Fe2O3 = (2 * Molar mass of Fe) + (3 * Molar mass of O)
Molar mass of Fe2O3 = (2 * 55.845 g/mol) + (3 * 16.00 g/mol)
Molar mass of Fe2O3 = 111.69 g/mol + 48.00 g/mol
Molar mass of Fe2O3 = 159.69 g/mol
Now we can use the molar mass of Fe2O3 to calculate the mass of iron(III) oxide that contains 58.7 g of iron.
Mass of iron(III) oxide = (Mass of iron / Molar mass of iron) * Molar mass of Fe2O3
Mass of iron(III) oxide = (58.7 g / 55.845 g/mol) * 159.69 g/mol
Mass of iron(III) oxide ≈ 169.33 g
Therefore, approximately 169.33 grams of iron(III) oxide contains 58.7 grams of iron.
To determine the mass of iron(III) oxide that contains 58.7 g of iron, we first need to know the molar mass of iron.
1. Find the molar mass of iron (Fe) on the periodic table. The molar mass of iron is 55.845 g/mol.
2. Determine the molar mass of iron(III) oxide (Fe2O3). Iron(III) oxide consists of two iron atoms and three oxygen atoms. The molar mass of oxygen (O) is 16.00 g/mol. Therefore, the molar mass of Fe2O3 is calculated as follows:
Molar mass of Fe2O3 = (2 × molar mass of Fe) + (3 × molar mass of O)
= (2 × 55.845 g/mol) + (3 × 16.00 g/mol)
= 111.69 g/mol + 48.00 g/mol
= 159.69 g/mol
3. Calculate the mass of iron(III) oxide using the formula:
Mass of Fe2O3 = (mass of Fe × molar mass of Fe2O3) / molar mass of Fe
= (58.7 g × 159.69 g/mol) / 55.845 g/mol
= 166.16 g
Therefore, 166.16 grams of iron(III) oxide contains 58.7 grams of iron.