A taxi cab charges a fixed amount of $1.50 in addition to $0.75 per mile. If Jasmine has $20 with her, what is the maximum number of miles she can ride in the cab? Write the equation and solve.

0.75 m + 1.50 = 20

0.75 m = 18.5

m = 18.5 / 0.75

To find the maximum number of miles Jasmine can ride in the cab, we need to determine how much money will be left after paying the fixed amount plus the cost per mile.

Let x be the number of miles Jasmine can ride.
The equation to represent the total cost is:
$1.50 + $0.75x = $20

To solve for x, we need to isolate x on one side of the equation.

Subtract $1.50 from both sides of the equation:
$0.75x = $20 - $1.50
$0.75x = $18.50

Divide both sides of the equation by $0.75:
x = $18.50 / $0.75

Simplify:
x = 24.67

Therefore, Jasmine can ride a maximum of 24.67 miles in the cab. Since we cannot have a fractional number of miles, we round down to the nearest whole number.

The maximum number of miles Jasmine can ride in the cab is 24 miles.

To find the maximum number of miles Jasmine can ride in the cab, we can set up an equation based on the given information.

Let's call the maximum number of miles Jasmine can ride "m". The total cost of the cab ride would then be $1.50 (the fixed amount) plus $0.75 per mile.

So, the equation becomes:

TotalCost = $1.50 + $0.75 * Number of miles

Since Jasmine has $20, we can set up another equation based on this:

TotalCost <= $20

Now, substitute the TotalCost from the first equation into the second equation:

$1.50 + $0.75 * Number of miles <= $20

Simplify the equation:

0.75 * Number of miles + $1.50 <= $20

Now we can solve for the maximum number of miles:

0.75 * Number of miles <= $20 - $1.50

0.75 * Number of miles <= $18.50

Now divide both sides of the equation by 0.75 to isolate the Number of miles:

Number of miles <= $18.50 / 0.75

Number of miles <= 24.6667

Since Jasmine cannot ride a fractional number of miles, the maximum number of miles she can ride in the cab is 24. Therefore, Jasmine can ride a maximum of 24 miles in the cab.