Evaluate ( if multiple values exist write down enough of them to show
a pattern):
(a) sin(iln(i))
(b) (1 + i)^2 + (1 + i)^4
(c) ln(−e)
sin(ix) = i sinh(x)
sinh(ln i) = (e^lni - e^-lni)/2 = (i - 1/i)/2 = (i+i)/2 = i
so, sin(i lni) = i * i = -1
1+i = √2 cis(π/4), so you have
2cis(π/2) + 4cis(π) = 2i -4
ln(-e) = 1 + πi