How many molecules of NH3 are produced from the reaction of 7 mols of Ca(OH)2 according to the following
(NH4)2SO4+Ca(OH)2=NH3+CaSO4+H2O
Balance the equation.
(NH4)2SO4 + Ca(OH)2 ==> 2NH3 + CaSO4 + 2H2O
From the equation, 1 mol Ca(OH)2 will produce 2 mols NH3; therefore, 7 mols Ca(OH)2 will produce 14 mols NH3.
1 mol NH3 contains 6.02E23 molecules NH3; therefore, 14 mols NH3 will produce 14*6E23 molecules NH3.
Well, according to the balanced equation, the stoichiometry between (NH4)2SO4 and NH3 is 1:1.
So, if you start with 7 mols of Ca(OH)2, and assuming it is completely consumed in the reaction, you will also produce 7 mols of NH3.
Therefore, you would have 7 molecules of NH3 produced.
Of course, if you're feeling a little "volatile," you could always sprinkle in some extra humor and say, "Well, you know, in the world of chemistry, everything is a-mole-zing. So, with 7 mols of Ca(OH)2, you can have a mo-le-than-adequate supply of 7 molecules of NH3! That's surely enough to make even the most stoic chemist crack a smile!"
To determine the number of NH3 molecules produced from the reaction of 7 moles of Ca(OH)2, we need to first determine the stoichiometry of the reaction.
The balanced chemical equation for the reaction is:
(NH4)2SO4 + Ca(OH)2 → NH3 + CaSO4 + H2O
From the equation, we can see that the stoichiometric ratio between Ca(OH)2 and NH3 is 1:1. This means that for every 1 mole of Ca(OH)2 reacted, we will produce 1 mole of NH3.
Therefore, if we have 7 moles of Ca(OH)2, we will also produce 7 moles of NH3.
To convert moles to molecules, we need to use Avogadro's number, which is 6.022 × 10^23 molecules per mole.
So, the number of NH3 molecules produced from the reaction of 7 moles of Ca(OH)2 is:
7 moles * (6.022 × 10^23 molecules/mole) = 4.2154 × 10^24 molecules of NH3.
Therefore, 4.2154 × 10^24 molecules of NH3 are produced.
To determine the number of molecules of NH3 produced from the reaction, we first need to understand the stoichiometry of the reaction. The balanced equation is:
(NH4)2SO4 + Ca(OH)2 → NH3 + CaSO4 + H2O
From the equation, we can see that for every 1 mol of Ca(OH)2, 1 mol of NH3 is produced. Therefore, we can say that the mole ratio of Ca(OH)2 to NH3 is 1:1.
Given that we have 7 mols of Ca(OH)2, we can conclude that the number of moles of NH3 produced will also be 7.
To determine the number of molecules, we can use Avogadro's number, which states that 1 mole of any substance contains 6.022 × 10^23 molecules.
Therefore, to calculate the number of molecules of NH3, we need to multiply the number of moles (7) by Avogadro's number:
Number of molecules = Number of moles * Avogadro's number
Number of molecules = 7 * 6.022 × 10^23
Number of molecules = 4.2154 × 10^24
So, from the given reaction, 7 mols of Ca(OH)2 will produce approximately 4.2154 × 10^24 molecules of NH3.