i need to rearrange the following equations, to make x the subject .

r = sx^2
2t

and

6y = 9 – 3x

can some 1 help me im realy stuck. i need to work it out step by step.

the 2t is meant 2 be under sx^2 meaning dived by

r= sx^2/2t

multipy both sides by 2t

r2t= sx^2
divide both sides by s

2rt/s= x^2

take the square root of each side

sqrt(2rt/s) = x
x=sqrt(2rt/s)

On the second, I will gladly critique your work. Start with adding 3x to both sides.

To rearrange the equation 6y = 9 - 3x to make x the subject, you can follow the steps below:

1. Start with the equation: 6y = 9 - 3x.
2. Add 3x to both sides of the equation to isolate the term containing x: 6y + 3x = 9.
3. Now, we need to get rid of the 6 on the left side of the equation. To do this, divide both sides of the equation by 6: (6y + 3x)/6 = 9/6.
4. Simplify the equation: y + (1/2)x = 3/2.
5. To isolate x, subtract y from both sides of the equation: (1/2)x = 3/2 - y.
6. Finally, multiply both sides of the equation by 2 to get rid of the 1/2 coefficient in front of x: 2 * (1/2)x = 2 * (3/2 - y).
7. Simplify: x = 3 - 2y.

Therefore, the rearranged equation with x as the subject is x = 3 - 2y.