Find an equation of the line that has slope m and y-intercept b. (Let x be the independent variable and y be the dependent variable.)
m = − 3/2
; b = 7/4
To find the equation of the line with a given slope (m) and y-intercept (b), we can use the slope-intercept form of a linear equation:
y = mx + b
Substituting the given values, we have:
y = (-3/2)x + 7/4
Therefore, the equation of the line with slope m = -3/2 and y-intercept b = 7/4 is y = (-3/2)x + 7/4.
To find the equation of a line with slope (m) and y-intercept (b), we can use the slope-intercept form of a linear equation, which is:
y = mx + b
Here, "m" represents the slope, and "b" represents the y-intercept.
Given that the slope (m) is -3/2 and the y-intercept (b) is 7/4, we can substitute these values into the equation to find the equation of the line:
y = (-3/2)x + 7/4
Simplifying this equation, we can multiply both the slope and the x coefficient by 2 to eliminate the fraction:
y = (-3/2)x + 7/4
y = -3x/2 + 7/4
So, the equation of the line with a slope of -3/2 and y-intercept of 7/4 is y = -3x/2 + 7/4.
review the point-slope form of a line:
y = mx+b
so plug in your numbers. They even gave you the values of m and b!