Two charges q1 and q2 exert a 90 N electrostatic force onto each other when they are 1 m apart. They are moved further away to a distance of 3 m. What will the new electrostatic force be?
30 N
810 N
10 N
270 N*
What is the gravitational force between two billiard balls of mass 156 g and 170 g that are 75 cm apart?
-2.36 x 10-12 N
2.36 x 10-12 N*
3.15 x 10-12 N
-3.15 x 10-12 N
Based on Coulomb's law, which quantities does the acceleration of a charged particle due to the Coulomb force depend on?
The acceleration depends on the charge but not on the mass.
The acceleration does not depend on the charge nor on the mass.
The acceleration depends on the mass but not on the charge.
The acceleration depends on both the charge and the mass.
Two masses m1 and m2 exert a gravitational force of 20 N onto each other when they are 4 m apart.
At what distance should they be to exert a force of 5 N onto each other?
64 m
16 m
8 m*
1 m
3 times the distance is 1/9 of the force
so 10 Newtons
To find the new electrostatic force between the charges q1 and q2 when they are moved further apart, we can use Coulomb's law. Coulomb's law states that the electrostatic force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The formula for the electrostatic force is given by:
F = k * (q1 * q2) / r^2
Where F is the electrostatic force, k is the Coulomb's constant, q1 and q2 are the charges, and r is the distance between the charges.
In this case, we know that the initial electrostatic force F1 is 90 N when the charges are 1 m apart. Let's call this distance r1. We want to find the new electrostatic force F2 when the charges are moved to a distance of 3 m. Let's call this distance r2.
To find the ratio of the distances, we can use the equation r2 = 3 * r1.
Now we can set up a proportion to find the ratio of the forces:
F1 / F2 = (r1 / r2)^2
Substituting the known values:
90 / F2 = (1 / 3)^2
Simplifying the equation:
90 / F2 = 1 / 9
Multiplying both sides by F2:
90 = F2 / 9
Multiplying both sides by 9:
810 = F2
Therefore, the new electrostatic force between the charges q1 and q2 when they are moved 3 m apart will be 810 N.
The correct answer is 810 N.