Find the average of all scores if there are:
ten scores of 9
eight scores of 8
ten scores of 7
three scores of 6
Round to one decimal place.
Wouldn't the average just be 7.8?
yes, because
(10*9 + 8*8 + 10*7 + 3*6)/(10+8+10+3) = 7.8
Before you post any more of these weighted average problems, John Mark, how about you show some of your work?
To find the average of all scores, you need to sum up all the individual scores and then divide the sum by the total number of scores. Given the information provided, we have:
10 scores of 9
8 scores of 8
10 scores of 7
3 scores of 6
Step 1: Calculate the sum of all the scores:
Total Sum = (10 * 9) + (8 * 8) + (10 * 7) + (3 * 6)
Calculate the values within parentheses:
Total Sum = 90 + 64 + 70 + 18
Total Sum = 242
Step 2: Calculate the total number of scores:
Total Number of Scores = 10 + 8 + 10 + 3
Total Number of Scores = 31
Step 3: Calculate the average by dividing the sum by the total number of scores:
Average = Total Sum / Total Number of Scores
Substituting in the values:
Average = 242 / 31
Average ≈ 7.806
Since the question asks to round to one decimal place, the average of all scores is approximately 7.8.