Tickets to a concert cost $9.00 for adults and $6.00 for students. A total of 950 people paid $7 500 to attend. How many students attended the concert?

350 students

9 a +6 s = 7 500 surely a typo

a = 950 - s
so
9 (950-s) + 6 s = 7500
8550 - 9 s + 6 s = 7500
-3 s = -1050
s = 1050/3 = 350

Well, it seems like the concert had a mix of adults and students. Let's use some clown math to figure this out.

Let's start by assigning variables:
A = number of adults
S = number of students

We know that the ticket price for an adult is $9.00 and for a student is $6.00. The total number of people attending the concert is 950. We also know that the total amount earned from ticket sales is $7,500.

So, we can set up two equations:

1) A + S = 950 (Equation 1, representing the total number of people attending)
2) 9A + 6S = 7500 (Equation 2, representing the total earnings)

Let's solve this circus puzzle!

Using Equation 1, we can express A in terms of S:
A = 950 - S

Now we can substitute this value of A into Equation 2:
9(950 - S) + 6S = 7500

After simulating this circus equation in the clown calculator, we find that there were 600 students attending the concert.

Let's assume the number of adults attending the concert is "x" and the number of students is "y".

According to the information given, the cost of a ticket for adults is $9.00 and the cost for students is $6.00.

So, the total cost paid by adults can be calculated as "9x" and the total cost paid by students can be calculated as "6y".

The total number of people attending the concert is given as 950, so we can write the equation as:

x + y = 950 ....(Equation 1)

The total amount paid by all attendees is given as $7,500, so we can write another equation as:

9x + 6y = 7,500 ....(Equation 2)

Now, let's solve these two equations to find the values of x and y.

Multiplying Equation 1 by 6, we get:

6x + 6y = 5,700 ....(Equation 3)

Subtracting Equation 3 from Equation 2, we can eliminate the variable 'y':

(9x + 6y) - (6x + 6y) = 7,500 - 5,700

3x = 1,800

Dividing both sides of the equation by 3, we find:

x = 600

Plugging the value of x into Equation 1, we can find the value of y:

600 + y = 950

y = 950 - 600

y = 350

Therefore, 350 students attended the concert.

To solve this problem, we can set up a system of equations. Let's represent the number of adult tickets sold as A and the number of student tickets sold as S.

From the given information, we know two things:
1. The total number of people who attended the concert is 950, so A + S = 950.
2. The total amount paid for tickets is $7,500, so 9A + 6S = 7,500.

We can solve this system of equations to find the values of A and S.

First, let's solve the first equation for A:
A = 950 - S.

Now we substitute this expression for A into the second equation:
9(950 - S) + 6S = 7,500.

Expanding and simplifying this equation, we get:
8,550 - 9S + 6S = 7,500.
-3S = 7,500 - 8,550.
-3S = -1,050.

Dividing both sides by -3, we find:
S = (-1,050) / (-3).
S = 350.

Therefore, 350 students attended the concert.