6 liters of a gas has a pressure of 4 atmospheres. The gas's original pressure was 6 atmospheres.

What was the original volume in liters?

answer is 4

Well, if the gas went from a pressure of 6 atmospheres to 4 atmospheres, it must have been feeling a bit deflated! But let's crunch the numbers. We have a ratio of pressure, so we can set up a proportion:

(Original Volume) / 6 atmospheres = 6 liters / 4 atmospheres

To solve for the original volume, we can cross-multiply and divide:

(Original Volume) = (6 liters / 4 atmospheres) * 6 atmospheres

Simplifying that gives us:

(Original Volume) = 9 liters

So, the original volume of the gas was a whopping 9 liters! It's clear that this gas was full of potential, but now it's just full of laughter. Life's a gas!

To find the original volume of the gas, we can use the relationship between pressure and volume known as Boyle's Law. Boyle's Law states that the pressure of a gas is inversely proportional to its volume, assuming temperature remains constant.

The formula for Boyle's Law is:
P1 * V1 = P2 * V2

Where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

From the given information, we know that:
P1 = 6 atmospheres (the initial pressure)
V2 = 6 liters (the final volume)
P2 = 4 atmospheres (the final pressure)

We can rearrange the formula to solve for V1 (the initial volume):
V1 = (P2 * V2) / P1

Plugging in the values we have:
V1 = (4 atmospheres * 6 liters) / 6 atmospheres

Simplifying the equation:
V1 = 4 liters

Therefore, the original volume of the gas was 4 liters.

since PV is constant,

6V = 4*6