Two masses m1 and m2 exert a gravitational force of 12 N onto each other when they are 6 m apart.
What will the gravitational force be if the masses are moved closer to be 3 m apart?
48 N
24 N
3 N
6 N***
Physics U5 L5 Force Predictions Connexus
1. D, 48 N
2. B, 10 N
3. D, −3.15 × 10−¹² N
4. C, The acceleration depends on both the charge and the mass.
5. B, 8 m
Physics U5 L5 Force Predictions Connexus
1. D, 48 N
2. B, 10 N
3. D, −3.15 × 10−¹² N
4. D, The acceleration depends on both the charge and the mass.
5. B, 8 m
cut the distance by half, multiply the force by 4, since F varies inversely as the square of the distance: 1/d^2
so like.... @ooblek i got 9 Lol
"suki" and "Awd0rable Angel" are 100% correct, life savers
To calculate the gravitational force between two masses, you can use Newton's law of universal gravitation, which states that the force is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.
The formula is:
F = G * (m1 * m2) / d^2
where F is the gravitational force, G is the gravitational constant (approximately 6.67430 x 10^-11 N m^2/kg^2), m1 and m2 are the masses, and d is the distance between them.
In the given scenario, the initial distance between the masses is 6 m, and the gravitational force is 12 N. We can use this information to solve for m1 * m2:
12 N = G * (m1 * m2) / (6 m)^2
Multiplying both sides of the equation by (6 m)^2 / G:
(m1 * m2) = 12 N * (6 m)^2 / G
Now, to find the gravitational force when the distance is reduced to 3 m, we can use the same formula and substitute in the new values:
F' = G * (m1 * m2) / (3 m)^2
Substituting the value of (m1 * m2) that we calculated earlier:
F' = G * (12 N * (6 m)^2 / G) / (3 m)^2
Simplifying the equation:
F' = 4 * 12 N
F' = 48 N
Therefore, the gravitational force between the two masses would be 48 N if they are moved closer to be 3 m apart.