What chemical equation represents the ability of a substance to donate a proton in water?
A. NH3 + H2O <-> NH4+ + OH-
B. CH3COOH + H2O <-> CH3COO- + H3O+
C. CH4 + 2O2 --> CO2 + H2O
D. CH3COOH + NaOH <-> CH3COOH + NaCl
I think the answer has to be either A or B. It can't be D because Cl is randomly introduced and C isn't a reaction in water. Can you guys help me our please.
So is the answer B?
Yes, the answer is B. The H from the -COOH group donates a proton to H2O to make the H2O become H3O^+ (the hydronium ion)
As Damon points out you should see that the CH3COOH on the left is missing the on on the right to become CH3COO- and the H2O on the right shows the H2O has been added to become H3O^+.
CH3COOH <<<< that H is a proton
CH3COO- <<<< that proton left.
H3O+ Oh, there it is !
Sure, I can help you with that! To determine the correct chemical equation that represents the ability of a substance to donate a proton in water, we need to understand the concept of an acid.
An acid is a substance that donates protons (H+) when dissolved in water. Based on this definition, the chemical equation that represents the ability of a substance to donate a proton in water is option B: CH3COOH + H2O <-> CH3COO- + H3O+.
In this equation, CH3COOH is the acid (acetic acid), which donates a proton (H+) to water (H2O) to form the hydronium ion (H3O+). Additionally, the acetate ion (CH3COO-) is formed as a result.
Option A (NH3 + H2O <-> NH4+ + OH-) represents the reaction between ammonia (NH3) and water, forming the ammonium ion (NH4+) and the hydroxide ion (OH-), but it does not involve donating a proton.
Option C (CH4 + 2O2 --> CO2 + H2O) represents the combustion reaction of methane (CH4) with oxygen (O2), producing carbon dioxide (CO2) and water (H2O), which is not related to the ability to donate a proton in water.
Option D (CH3COOH + NaOH <-> CH3COOH + NaCl) represents the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH), resulting in the formation of sodium acetate (CH3COONa) and sodium chloride (NaCl). It does not involve donating a proton, but rather the exchange of ions between the acid and the base.
Therefore, the correct answer is B.