A sample of CaCO3 was heated, causing it to form CaO
and CO2 gas. Solid CaO remained behind, while the CO2
escaped to the atmosphere. If the CaCO3 weighed 612 g
and the CaO weighed 343 g, how many grams of CO2 were
formed in the reaction?
Is the answer 269 grams of CO2?
yes. Good work.
To find the number of grams of CO2 formed in the reaction, we need to calculate the difference in weight between the initial CaCO3 and the resulting CaO.
Given:
Weight of CaCO3 = 612 g
Weight of CaO = 343 g
To find the weight of CO2 formed, we subtract the weight of CaO from the weight of CaCO3:
Weight of CO2 = Weight of CaCO3 - Weight of CaO
Weight of CO2 = 612 g - 343 g = 269 g
Therefore, the correct answer is 269 grams of CO2 were formed in the reaction.
To find the number of grams of CO2 formed in the reaction, we need to determine the difference in weight between the initial CaCO3 and the remaining CaO.
First, we calculate the weight of CaCO3 that was converted into CaO:
Weight of CaCO3 = 612 g
Weight of CaO = 343 g
Therefore, the weight of CaCO3 that was converted = 612 g - 343 g = 269 g
Since CaCO3 decomposes to form CaO and CO2 in a 1:1 ratio, the weight of CO2 formed will also be 269 g.
So, the correct answer is 269 grams of CO2.