When 1.0 mole of liquid Br2 is converted to Br2 vapour at 25.0oC and 1.0 atm pressure, 7.3 Kcal of heat is absorbed, and 0.59 kcal of expansion work is done by the system. Calculate ΔU for this process
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Double Pi, if you can't help, do not respond. Leave the question alone.
To calculate ΔU (change in internal energy) for this process, we need to use the First Law of Thermodynamics, which states that the change in internal energy of a system is equal to the heat absorbed by the system minus the work done by the system.
ΔU = Q - W
Given:
Heat absorbed by the system (Q) = 7.3 kcal
Work done by the system (W) = 0.59 kcal
Substituting the given values into the formula, we have:
ΔU = 7.3 kcal - 0.59 kcal
Now we can calculate the change in internal energy:
ΔU = 6.71 kcal
Therefore, the change in internal energy for this process is 6.71 kcal.