1. Al + Pb(NO3)2 ----> Al(NO3)3 + Pb
2. FeS + O2 ----> Fe2O3 + SO2
3. C3H8 + O2 ----> CO2 + H2O
I need some help balancing these equations. Thank you very much!
Trial and error. Here is how you go about the first one. Rule 1. You must balance ONLY by changing the coefficients. You may NOT change any of the subscripts.
Al + Pb(NO3)2 ----> Al(NO3)3 + Pb
Look at the nitrate on the right side. There are 3 of them and 2 on the left so we know right away, if we are to use whole numbers, that we must multiply one by 2 and the other by 3.
Al + 3Pb(NO3)2 ==> 2Al(NO3)3 + Pb
Now you see we have 2 Al on the right. We can make Al balance by place a 2 as a coefficient on the left for Al. Now we have
2Al + 3Pb(NO3)2 ==> 2Al(NO3)2 + Pb
Now we see 3 Pb on the left and we can fix that by placing a 3 for Pb.
2Al + 3Pb(NO3)2 ==> 2Al(NO3)3 + 3Pb
We ALWAYS check it to see that everything balances.
I see 2 Al atoms on the left and right.
I see 3 Pb atoms on the left and on the right.
I see 6 NO3^- on the left and 6 on the right. So everything balances.
The others are done the same way. Post your work if you have problems. Check this yourself to make sure I didn't goof.
Sure, I can help you balance these chemical equations step-by-step.
1. Al + Pb(NO3)2 -> Al(NO3)3 + Pb
To balance this equation, start by counting the number of atoms on each side.
On the left side (reactants):
- 1 Aluminum (Al) atom
- 1 Lead (Pb) atom
- 2 Nitrogen (N) atoms
- 6 Oxygen (O) atoms (2 from Pb(NO3)2)
On the right side (products):
- 1 Aluminum (Al) atom
- 3 Nitrogen (N) atoms (3 from Al(NO3)3)
- 9 Oxygen (O) atoms (3 from Al(NO3)3 and 6 from Pb(NO3)2)
To balance the atoms, you can start by balancing the major atoms first. In this case, let's start with Nitrogen:
Balance the nitrogen atoms by multiplying the reactant and product with the lowest amount of Nitrogen by a suitable factor.
In this case, multiply Pb(NO3)2 by 3, so you have 3 nitrogen atoms on both sides:
Al + 3Pb(NO3)2 -> Al(NO3)3 + Pb
Now let's look at Oxygen:
Count the oxygen atoms again:
- On the left side: 6 oxygen atoms from Pb(NO3)2
- On the right side: 9 oxygen atoms from Al(NO3)3 and Pb(NO3)2
To balance the oxygen, you can multiply the Al(NO3)3 by 3:
Al + 3Pb(NO3)2 -> 3Al(NO3)3 + Pb
Finally, let's balance the lead (Pb) atoms:
Count the lead atoms again:
- On the left side: 1 lead atom (Pb)
- On the right side: 1 lead atom (Pb)
The equation is now balanced:
2Al + 3Pb(NO3)2 -> 3Al(NO3)3 + 3Pb
2. FeS + O2 -> Fe2O3 + SO2
To balance this equation, start by counting the number of atoms on each side.
On the left side (reactants):
- 1 Iron (Fe) atom
- 1 Sulfur (S) atom
On the right side (products):
- 2 Iron (Fe) atoms (2 from Fe2O3)
- 3 Oxygen (O) atoms (3 from Fe2O3)
- 1 Sulfur (S) atom
- 2 Oxygen (O) atoms (2 from SO2)
To balance the atoms, you can start with Iron (Fe):
Balance the iron atoms by multiplying FeS by 2:
2FeS + O2 -> Fe2O3 + SO2
Next, let's balance the sulfur (S) atoms:
The sulfur atom is already balanced, so no changes are needed.
Finally, let's balance the oxygen (O) atoms:
On the left side: 2 oxygen atoms from O2
On the right side: 3 oxygen atoms from Fe2O3 and 2 oxygen atoms from SO2
To balance the oxygen, you can multiply SO2 by 3:
2FeS + O2 -> Fe2O3 + 3SO2
The final balanced equation is:
2FeS + 3O2 -> Fe2O3 + 3SO2
3. C3H8 + O2 -> CO2 + H2O
To balance this equation, start by counting the number of atoms on each side.
On the left side (reactants):
- 3 Carbon (C) atoms
- 8 Hydrogen (H) atoms
- 2 Oxygen (O) atoms (from O2)
On the right side (products):
- 1 Carbon (C) atom (from CO2)
- 2 Oxygen (O) atoms (from CO2)
- 2 Hydrogen (H) atoms (from H2O)
To balance the atoms, you can start with Carbon (C):
Balance the carbon atoms by multiplying CO2 by 3:
C3H8 + O2 -> 3CO2 + H2O
Next, let's balance the hydrogen (H) atoms:
On the left side: 8 hydrogen atoms from C3H8
On the right side: 2 hydrogen atoms from H2O
To balance the hydrogen atoms, you can multiply H2O by 4:
C3H8 + O2 -> 3CO2 + 4H2O
Finally, let's balance the oxygen (O) atoms:
On the left side: 2 oxygen atoms from O2
On the right side: 6 oxygen atoms from 3CO2 and 4 oxygen atoms from 4H2O
To balance the oxygen atoms, you can multiply O2 by 6:
C3H8 + 6O2 -> 3CO2 + 4H2O
The final balanced equation is:
C3H8 + 6O2 -> 3CO2 + 4H2O
I hope this helps!
Sure! I'd be happy to help you balance these chemical equations. Balancing chemical equations is a process of ensuring that the same number of each type of atom is present on both sides of the equation. Let's go through each equation step by step:
1. Al + Pb(NO3)2 -> Al(NO3)3 + Pb
To balance the equation, we need to start by counting the number of atoms for each element on both sides of the equation:
On the left-hand side:
- Aluminum (Al): 1
- Lead (Pb): 1
- Nitrogen (N): 2
- Oxygen (O): 6 (3 from Pb(NO3)2 and 3 from Al(NO3)3)
On the right-hand side:
- Aluminum (Al): 1
- Nitrogen (N): 3
- Oxygen (O): 9 (3 from Al(NO3)3 and 6 from Pb(NO3)2)
Now, let's balance the equation by adjusting the coefficients in front of each compound:
Al + 3Pb(NO3)2 -> 2Al(NO3)3 + 3Pb
2. FeS + O2 -> Fe2O3 + SO2
On the left-hand side:
- Iron (Fe): 1
- Sulfur (S): 1
- Oxygen (O): 2 (from O2)
On the right-hand side:
- Iron (Fe): 2 (from Fe2O3)
- Sulfur (S): 1
- Oxygen (O): 5 (3 from Fe2O3 and 2 from SO2)
To balance the equation:
4FeS + 7O2 -> 2Fe2O3 + 4SO2
3. C3H8 + O2 -> CO2 + H2O
On the left-hand side:
- Carbon (C): 3 (from C3H8)
- Hydrogen (H): 8 (from C3H8)
- Oxygen (O): 2 (from O2)
On the right-hand side:
- Carbon (C): 1 (from CO2)
- Hydrogen (H): 2 (from H2O)
- Oxygen (O): 3 (from CO2 and H2O)
To balance the equation:
C3H8 + 5O2 -> 3CO2 + 4H2O
That's it! The equations have been successfully balanced by adjusting the coefficients in front of each compound to ensure the same number and type of atoms on both sides of the equation.