At Wendy's a cheeseburger has 200 fewer calories than a large fries. Two cheeseburgers are a large fries have 1100 calories. How many calories are in each item? Let c represent the number of calories in a cheeseburger and let f represent the number of calories in an order of fries.

Question

At Wendy's a cheeseburger has 200 fewer calories than a large fries. Two cheeseburgers are a large fries have 1100 calories. How many calories are in each item? Let c represent the number of calories in a cheeseburger and let f represent the number of calories in an order of fries.

Answer 1

c = f - 200

2c + f = 1100
add these together and you have
3c = 900
c = 300
so, f = 500

Answer 2

Let's solve the problem step-by-step:

Step 1: Assign variables.
Let c be the number of calories in a cheeseburger.
Let f be the number of calories in an order of fries.

Step 2: Set up equations.
According to the problem, "At Wendy's, a cheeseburger has 200 fewer calories than a large fries." This can be written as:
c = f - 200

Also, the problem states that "Two cheeseburgers and a large fries have a total of 1100 calories." This can be written as:
2c + f = 1100

Step 3: Solve the equations.
Substitute the value of c from the first equation into the second equation:
2(f - 200) + f = 1100
2f - 400 + f = 1100
3f = 1500
f = 1500/3
f = 500

Step 4: Calculate the number of calories in a cheeseburger.
Substitute the value of f into the first equation:
c = 500 - 200
c = 300

Step 5: Answer the question.
Therefore, there are 300 calories in a cheeseburger and 500 calories in an order of fries.

Answer 3

To solve this problem, we can set up a system of equations based on the given information.

Let's start by assigning variables:
c = number of calories in a cheeseburger
f = number of calories in an order of fries

According to the problem:
"A cheeseburger has 200 fewer calories than a large fries" can be written as:
c = f - 200

Also, "Two cheeseburgers and a large fries have 1100 calories" can be written as:
2c + f = 1100

Now we have a system of equations:
c = f - 200
2c + f = 1100

To solve this system, we can use substitution or elimination methods. Here, we will use the substitution method.

Substitute the value of c from the first equation into the second equation:
2(f - 200) + f = 1100

Distribute:
2f - 400 + f = 1100

Combine like terms:
3f - 400 = 1100

Add 400 to both sides:
3f = 1500

Divide both sides by 3:
f = 500

Now we have the value of f, which represents the number of calories in an order of fries. We can substitute this value back into any of the original equations to find c.

Using the first equation:
c = f - 200
c = 500 - 200
c = 300

So, there are 500 calories in an order of fries and 300 calories in a cheeseburger.