James has a collection of new nickels and quarters. He has a total of 50 coins worth $10.30. How many of each coin does he have? Let n represent the number of nickles and q represent the number of quarters.
add up the coins and their values:
n+q = 50
5n+25q = 1030
Now crank it out
Let's solve this problem step by step using algebra.
Step 1: Write out the information given in the problem.
James has a collection of new nickels and quarters.
He has a total of 50 coins worth $10.30.
Let n represent the number of nickels.
Let q represent the number of quarters.
Step 2: Write out the equations based on the information given.
We can write two equations based on the number of coins and their total value:
Equation 1: n + q = 50 (because James has a total of 50 coins)
Equation 2: 0.05n + 0.25q = 10.30 (because the total value is $10.30)
Step 3: Simplify and solve the system of equations.
We can solve the equations by using the substitution method or the elimination method. Let's use the elimination method.
To eliminate n from the equation, multiply Equation 1 by -0.05:
-0.05(n + q) = -0.05(50)
-0.05n - 0.05q = -2.50
Now add this equation to Equation 2:
0.05n + 0.25q + (-0.05n - 0.05q) = 10.30 + (-2.50)
0.20q = 7.80
Divide both sides of the equation by 0.20:
q = 7.80 / 0.20
q = 39
Now substitute the value of q back into Equation 1:
n + 39 = 50
n = 50 - 39
n = 11
So, James has 11 nickels (n) and 39 quarters (q).
To solve this problem, we can create a system of equations based on the given information.
Let's start by defining the variables:
n = number of nickels
q = number of quarters
We have two equations from the problem statement:
1. James has a total of 50 coins:
n + q = 50
2. The total value of the coins is $10.30:
0.05n + 0.25q = 10.30
Now, let's solve this system of equations using the substitution method.
From the first equation, we can express n in terms of q:
n = 50 - q
Now, substitute this expression for n in the second equation:
0.05(50 - q) + 0.25q = 10.30
Simplify the equation:
2.5 - 0.05q + 0.25q = 10.30
0.2q = 7.8
q = 7.8 / 0.2
q = 39
Now that we know the number of quarters (q = 39), we can substitute this value back into the first equation to find n:
n + 39 = 50
n = 50 - 39
n = 11
Therefore, James has 11 nickels (n = 11) and 39 quarters (q = 39).