solve each system by elimination
15x - y = 3
5x - 10y = 30
im stuck with what to do first
multiply the second line by 3 and ypu have
15x - y = 3
15x - 30y = 90
now subtract and that leaves
29y = -87
y = -3
so, since 15x-(-3) = 3, x=0
I got (6/15 , 3)
To solve the system of equations by elimination, you need to eliminate one variable by adding or subtracting the equations. Here's how to start:
Step 1: Multiply each equation by a constant to make the coefficients of either the x or y terms equal or opposite.
Looking at the given equations:
15x - y = 3 (Equation 1)
5x - 10y = 30 (Equation 2)
Let's multiply Equation 1 by 10 and Equation 2 by 2 to make the coefficients of y equal:
(10) * (15x - y) = (10) * (3) (Equation 1)
(2) * (5x - 10y) = (2) * (30) (Equation 2)
Simplify the equations:
150x - 10y = 30 (Equation 3)
10x - 20y = 60 (Equation 4)
Step 2: Now, we will eliminate the y term from the equations by adding them together.
Add Equation 3 and Equation 4 together:
(150x - 10y) + (10x - 20y) = 30 + 60
Simplify the equation:
160x - 30y = 90 (Equation 5)
Now, you have a new equation:
160x - 30y = 90
This is a simplified form of the original system of equations after the elimination method.