In which scenario do you use geometric distribution to solve?
-Find the number of times a tossed coin lands on tails in 10 trials.
-Determine the number trials to do to have a tossed coin land on tails 8 times.
-Determine the probability of tossed coin and landing on tails.
-Find the probability of not getting tails until the 6th toss of the coin.
Find the probability of not getting tails until the 6th toss of the coin.
The geometric distribution is used to solve the following scenario:
- Determine the number of trials needed to achieve a specific outcome, such as the number of trials needed for a tossed coin to land on tails a certain number of times. For example, "Determine the number of trials needed for a tossed coin to land on tails 8 times."
The scenario in which you would use the geometric distribution is when you are interested in finding the probability of a specific event occurring for the first time after a certain number of trials.
In this case, the correct scenario where you would use the geometric distribution is:
-Find the probability of not getting tails until the 6th toss of the coin.
To solve this problem, you need to know the probability of getting tails on a single toss of the coin. Let's say this probability is p.
The geometric distribution formula for finding the probability of an event occurring for the first time on the nth trial is:
P(X = n) = (1-p)^(n-1) * p
Where:
P(X = n) is the probability of the event occurring for the first time on the nth trial
p is the probability of the event occurring on a single trial
In the given scenario, you want to find the probability of not getting tails until the 6th toss of the coin. This means you want to find P(X = 6).
Now, you can plug in the values into the formula and calculate the probability:
P(X = 6) = (1-p)^(6-1) * p
Once you have determined the value of p, you can use it in the formula to find the probability of the desired outcome.