A "Bayer brand of aspirin was dissolved in some sodium hydroxide and transferred to a 100.0 ml volumetric flask and diluted to the mark with distilled water. A 2.2ml aliquot of this solution was transferred to a second 100.0 ml volumetric flask and diluted to the mark with iron (IIl) chloride solution. The concentration of the iron (II) salicylate complex was found to be 0.048mM. What was the original concentration of A.S.A (aspirin) in the original solution, in mM?

Question

A "Bayer brand of aspirin was dissolved in some sodium hydroxide and transferred to a 100.0 ml volumetric flask and diluted to the mark with distilled water. A 2.2ml aliquot of this solution was transferred to a second 100.0 ml volumetric flask and diluted to the mark with iron (IIl) chloride solution. The concentration of the iron (II) salicylate complex was found to be 0.048mM. What was the original concentration of A.S.A (aspirin) in the original solution, in mM?

Answer 1

The numbers have changed since your first post below but the math process still is the same.

mM ASA in the original 100 mL volumetric flask will be
0.048 mM x (100 mL/2.2 mL) = ? mM.

Answer 2

^ Thank you so much @DrBob222. Greatly appreciated!

Answer 3

To find the original concentration of aspirin (ASA) in the original solution, you need to use the concept of dilution and the information provided in the question.

Let's break down the steps to find the original concentration of ASA:

Step 1: Calculate the dilution factor
The first 100.0 ml volumetric flask contains the dissolved Bayer brand of aspirin solution. A 2.2 ml aliquot from this solution is transferred to the second 100.0 ml volumetric flask and diluted to the mark with iron (III) chloride solution.

The dilution factor can be calculated as the ratio of the final volume to the initial volume:
Dilution factor = Volume of second flask / Volume of first flask
Dilution factor = 100.0 ml (final volume) / 2.2 ml (initial volume)

Step 2: Calculate the concentration of ASA in the second flask
The concentration of the iron (II) salicylate complex in the second flask is provided as 0.048 mM.

Step 3: Calculate the concentration of ASA in the original solution
The concentration of ASA in the second flask is equal to the concentration of ASA in the original solution multiplied by the dilution factor:
Concentration of ASA in original solution = Concentration of ASA in second flask / Dilution factor

Now, let's calculate the original concentration of ASA using the given information:
Concentration of ASA in original solution = 0.048 mM / (100.0 ml / 2.2 ml)

Simplifying the expression:
Concentration of ASA in original solution = 0.048 mM / 45.45

The original concentration of ASA in the original solution is approximately 0.00106 mM (rounded to five decimal places).