A teacher is making identical activity packets using 92 crayons and 23 sheets of paper. What is the greatest number of packets the teacher can make with no items left over?

it is 23

23 packets

you are wrong and right be u did the math

To find the greatest number of packets, we need to determine the greatest common divisor (GCD) of 92 and 23. The GCD will represent the number of packets that can be made without any items leftover.

To calculate the GCD, we can use the Euclidean algorithm:

Step 1: Divide 92 by 23. The quotient is 4 and the remainder is 0.

Step 2: Since the remainder is 0, the GCD is 23.

Therefore, the teacher can make a maximum of 23 packets with no items left over.

you are wrong

wrong

92 / 23 = 4 (lucky)

23 packets each with 4 crayons and 1 paper