Calculate the energy needed to heat the cube of silver, with a volume of 19.0 cm3 , from 15 ∘C to 28 ∘C
Why did the cube of silver go to the gym? Because it wanted to get ripped!
But on a serious note, to calculate the energy needed to heat the cube of silver, we can use the formula:
Q = mcΔT,
where Q represents the heat energy, m represents the mass of the silver cube, c represents the specific heat capacity of silver, and ΔT represents the change in temperature.
Given:
Volume of the cube = 19.0 cm³
Since we know the volume and density of silver (10.5 g/cm³), we can calculate the mass of the cube:
Mass = Volume × Density
Mass = 19.0 cm³ × 10.5 g/cm³
Now, to convert cm³ to m³, we divide the volume by 1,000,000:
Mass = 19.0 × 10^(-6) m³ × 10.5 g/cm³
Next, let's convert grams to kilograms:
Mass = 19.0 × 10^(-6) m³ × 10.5 × 10³ kg/m³
Now we can calculate the mass:
Mass = 0.1995 kg
The specific heat capacity of silver is approximately 0.235 J/g°C.
Now let's calculate the change in temperature:
ΔT = (28 °C) - (15 °C)
ΔT = 13 °C
Now we can plug the values into the formula:
Q = mcΔT
Q = (0.1995 kg) × (0.235 J/g°C) × (13 °C)
Calculating the expression:
Q = 0.6031 J
So, the energy needed to heat the cube of silver from 15 °C to 28 °C is approximately 0.6031 Joules.
To calculate the energy needed to heat the cube of silver, you can use the formula:
Q = mcΔT
where:
Q = Energy needed
m = Mass of the silver cube (density x volume)
c = Specific heat capacity of silver
ΔT = Change in temperature
Let's calculate each component step-by-step:
Step 1: Calculate the mass of the silver cube
We need to know the density of silver to calculate the mass. The density of silver is approximately 10.5 g/cm3.
Density of silver (ρ) = 10.5 g/cm3
Volume of the cube (V) = 19.0 cm3
Mass (m) = Density x Volume
m = 10.5 g/cm3 x 19.0 cm3
m = 199.5 g
The mass of the silver cube is 199.5 g.
Step 2: Calculate the change in temperature
ΔT = Final temperature - Initial temperature
ΔT = 28 °C - 15 °C
ΔT = 13 °C
The change in temperature is 13 °C.
Step 3: Determine the specific heat capacity of silver
The specific heat capacity of silver is approximately 0.24 J/g°C.
The specific heat capacity of silver is 0.24 J/g°C.
Step 4: Calculate the energy needed using the formula:
Q = mcΔT
Q = (mass) x (specific heat capacity) x (change in temperature)
Q = 199.5 g x 0.24 J/g°C x 13 °C
Now, we can calculate Q:
Q ≈ 619.392 J
The energy needed to heat the cube of silver from 15 °C to 28 °C is approximately 619.392 J.
To calculate the energy needed to heat the cube of silver, we can use the formula:
Q = mcΔT
Where:
Q is the heat energy
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
First, we need to determine the mass of the silver cube. We can do this by using the volume and the density of silver.
The density of silver is approximately 10.5 g/cm3. Therefore, the mass can be calculated as:
mass = density * volume
mass = 10.5 g/cm3 * 19.0 cm3
mass ≈ 199.5 g
Next, we need to calculate the change in temperature (ΔT):
ΔT = final temperature - initial temperature
ΔT = 28 °C - 15 °C
ΔT = 13 °C
Now, we need to find the specific heat capacity of silver. The specific heat capacity of silver is approximately 0.24 J/g°C.
Finally, we can calculate the heat energy (Q) using the formula:
Q = mcΔT
Q = 199.5 g * 0.24 J/g°C * 13 °C
Q ≈ 610.74 J
Therefore, the energy needed to heat the cube of silver from 15 °C to 28 °C is approximately 610.74 Joules.
what is the specific heat of silver. What's the density of silver.
q = mass Ag x specific heat Ag x (delta T)
The problem didn't give you the mass but you can calculate it from the volume given. volume = mass/density.
Post your work if you get stuck.