This is going to be hard to explain, but here goes!
Four resistors, R1 = 30.0 ohm, R2 = 52.0 ohm, R3 = 93.0 ohm and R4 = 17.0 ohm, are connected to a battery with a terminal voltage of 18.0 V, as shown in the figure below.
____R1____R2__________
| |
|_______R3_____________|
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|___R4____ -(18 V)+____|
(that was the best i could do..)
Determine the power lost in the R2 = 52.0 ohm resistor.
To determine the power lost in the R2 resistor, we need to calculate the current passing through it and then use the formula for power, P = I²R.
First, we can apply Ohm's Law to find the current passing through the resistors. Ohm's Law states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R).
For R1: I1 = V/R1 = 18.0V / 30.0Ω
For R2: I2 = V/R2 = 18.0V / 52.0Ω
For R3: I3 = V/R3 = 18.0V / 93.0Ω
For R4: I4 = V/R4 = 18.0V / 17.0Ω
Now, we have the current passing through each resistor. We can use this information to find the power lost in R2.
The formula for power is P = I²R, where P is power, I is current, and R is resistance.
To find the power lost in R2, we can use the formula: PR2 = I2² * R2, where I2 is the current passing through R2.
Using the values we calculated earlier:
PR2 = (I2)² * R2 = (18.0V / 52.0Ω)² * 52.0Ω
Now, you can calculate the power lost in the R2 = 52.0 ohm resistor using the given values above.