A man jogs at a speed of 1.8 m/s. His dog

waits 2.5 s and then takes off running at a
speed of 2.7 m/s to catch the man.
How far will they have each traveled when
the dog catches up with the man?
Answer in units of m

when the dog catches up , they both will have traveled the same distance

t * 1.8 m/s = (t - 2.5 s) * 2.7 m/s

solve for the time the man jogged , then find the distance