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In a large school, it is possible to divide the pupils into groups of equal numbers of 24,30 and 32 and have no pupils left over. Find the least number of pupils that makes this possible.

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Gideon

  1. 24 = 2^3 * 3
    30 = 2*3*5
    32 = 2^5
    So, LCM(24,30,32) = 2^5 * 3 * 5 = 480

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    oobleck

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