if a force of 50 N stretches a spring 0.10 m, what is the spring constant?
F = k x
50 = k (.1)
k = 500 N/m
To find the spring constant, you can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.
Hooke's Law equation is: F = k * x
Where:
F is the force applied to the spring (in Newton, N),
k is the spring constant (in Newton per meter, N/m),
x is the displacement of the spring from its equilibrium position (in meter, m).
Given:
Force, F = 50 N
Displacement, x = 0.10 m
Substituting the given values in the Hooke's Law equation, we get:
50 N = k * 0.10 m
To find the spring constant, we need to solve for k. Dividing both sides of the equation by 0.10 m, we get:
k = 50 N / 0.10 m
Calculating it, the spring constant is:
k = 500 N/m
Therefore, the spring constant is 500 N/m.