in a bucket of fruit there are 6 grapes,11 bananas and 13 oranges. If one fruit is chosen random,what is the probability that the fruit is either grape or banana.
Isn`t what i`m looking for
But thanks for your help
there are 30 fruits in all -- 17 are either grapes or bananas, so
17/30
To find the probability that the fruit is either a grape or a banana, we need to determine the total number of possible outcomes (i.e., the total number of fruits) and the number of favorable outcomes (i.e., the number of grapes or bananas).
Total number of fruits = 6 grapes + 11 bananas + 13 oranges = 30 fruits
Number of grapes or bananas = 6 grapes + 11 bananas = 17 fruits
Therefore, the probability of selecting a grape or banana is:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)
= 17 fruits / 30 fruits
= 17/30
So, the probability that the fruit chosen is either a grape or a banana is 17/30.
To find the probability that the fruit chosen is either a grape or a banana, we need to first determine the total number of fruits in the bucket, as well as the number of grapes and bananas.
In this case, the total number of fruits = 6 grapes + 11 bananas + 13 oranges = 30 fruits.
The number of grapes = 6, and the number of bananas = 11.
Therefore, the probability of choosing a grape or a banana is calculated by dividing the number of desired outcomes (grapes + bananas) by the total number of possible outcomes (total fruits):
Probability = (Number of desired outcomes) / (Total number of possible outcomes)
Probability = (Number of grapes + Number of bananas) / (Total number of fruits)
Probability = (6 + 11) / 30
Probability = 17 / 30
So, the probability that the fruit chosen is either a grape or a banana is 17/30.