The formula for rust is fe2o3 how many moles of (fe) are present in 30 g of rust ?

mm = molar mass

g Fe in 30 g Fe2O3 = 30 x (2*mm Fe/mm Fe2O3) = ?
mols Fe = g Fe/atomic mass Fe = ?

By the way, the formula for rust is much more complicated than Fe2O3. Also the formula appears to change with time and the amount of moisture in the reaction.

To find the number of moles of iron (Fe) present in 30 g of rust (Fe2O3), we need to follow these steps:

1. Determine the molar mass of rust (Fe2O3):
- The molar mass of Fe (iron) is 55.845 g/mol.
- The molar mass of O (oxygen) is 15.999 g/mol.
- Since there are two iron atoms in rust, the total molar mass of Fe2O3 is:
(2 * 55.845 g/mol) + (3 * 15.999 g/mol) = 159.69 g/mol.

2. Use the molar mass to calculate the number of moles:
- Divide the given mass by the molar mass:
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles = 30 g / 159.69 g/mol
Number of moles ≈ 0.188 moles (rounded to three decimal places).

Therefore, there are approximately 0.188 moles of iron (Fe) present in 30 g of rust (Fe2O3).