Mathematics
 👍
 👎
 👁

 👍
 👎
👤oobleck 
 👍
 👎
Respond to this Question
Similar Questions

MATH
the fist term of a geometric series is 1, the nth term is 128 and the sum of the n term is 225. Find the common ratio and the number of terms?

Mathematics
The third and sixth terms of a geometric progression(G.P) are 1/4 & 1/32 respectively. Find 1. The first term 2.the common ratio 3. The seventh term

Maths
The 3rd and 4th term of geometric progression are 4 and 8 respectively find: The first term and common ratio, The sum of the first 10 term, The sum of infinity.

mathalgebra 1
Find the 6th term of the geometric sequence whose common ratio is 1/3 and whose first term is 7.

Maths
The second term of a GP is12 more than the first term,given that the common ratio is half of the first term.Find the third term of the GP?

math
a GP has a first term of A,a common ratio of r and its 6th term is 768. another GP has a first term of a,a common ratio of 6r and its 3rd term is 3456. evaluate a and r

f/math
the common ratio of a g.p is 2.if the 5th term is greater than the first term by 45, find the 5tth term

math
The third,fourth and eight term of A.P form first three consecutive term of G.P.if the sum of the first ten term of A.P is 85.calculate the first term of both A.P and G.P,common ratio and sum of 5 term of G.P

geometric progression
the 3rd term of a gpis 10 and the 6th term is 80 find the common ratio No2 if the 2nd term of a gp is 4 and the 5th term is 1over 16,the7th term is_

mathematics
in a geometric progression, the first term is a and the common ratio is r. the sum of the first two terms is 12 and the third term is 16. a) determine the ratio (ar^2)/a+ar( aready found the answer as 4/3) b) if the first term is

Mathematics
The second and fifth terms of a geometric progression (g.p) are 1 and 8 respectively. Find the common ratio,first term, and the eight term.

math
A G.P has 6 terms. If the 3rd and 4th term are 28 and 56 respectively find common ratio, first term and the sum of the G.P.
You can view more similar questions or ask a new question.