A box contains different coloured counters. The probabilities of randomly selected a particular type of counter are as follows: Purple = 1/10, Yellow = 1/5, Orange = 3/5
Are there any other coloured counters beside Purple, Yellow and Orange in the box?
Calculate the probability of selecting the other colour
Fluff you I don't Know this teach this.
Based on the given information, we know the probabilities for purple, yellow, and orange counters, but we don't have information about any other colored counters. Therefore, we cannot determine the probability of selecting any other color from the box.
To determine whether there are any other colored counters in the box, we need to add up the probabilities of all the given colors and see if it equals 1.
Given probabilities:
Purple = 1/10
Yellow = 1/5
Orange = 3/5
To calculate the probability of selecting the "other" color, we need to find the total probability of all the other colors combined.
Let's call the probability of the "other" color P(Other).
P(Other) = 1 - P(Purple) - P(Yellow) - P(Orange)
Substituting the given values:
P(Other) = 1 - 1/10 - 1/5 - 3/5
= 1 - 1/10 - 2/10 - 6/10
= 1 - 9/10
= 1/10
Therefore, the probability of selecting the "other" color is 1/10.
Yes, since 1/10 + 1/5 + 3/5 = 9/10 which is not equal to 1
so the prob of selecting the other colour(s), there could be more than one other, is 1/10