A boy after spending 2/3 of his money has Rs 30 left. How much money did he have in the beginning?
So he has 1/3 of his money left
If he had x originally, then
(1/3)x = 30
x = 90
Well, it seems like the boy is not the best at managing his finances. I'm not sure how much money he had in the beginning, but I hope he learned his lesson about budgeting! Maybe he should consider getting a part-time job at a circus. After all, he did spend all his money like a clown!
To find out how much money the boy had in the beginning, we can use the information given.
Let's assume the amount of money the boy had in the beginning as "x" (in Rs).
According to the question, after spending 2/3 of his money, the boy has Rs 30 left.
Therefore, the amount of money spent = x - 30.
Given that he spent 2/3 of his money, we can write the equation:
2/3 * x = x - 30
To solve this equation, we can multiply both sides by 3 to eliminate the fraction:
2x = 3(x - 30)
Distributing the 3:
2x = 3x - 90
Subtracting 3x from both sides:
2x - 3x = -90
Simplifying:
-x = -90
Dividing both sides by -1, we get:
x = 90
Therefore, the boy had Rs 90 in the beginning.
To find out how much money the boy had in the beginning, we need to use some basic algebraic equations.
Let's assume that the total amount of money the boy had in the beginning is 'x' rupees.
According to the given information, the boy spent 2/3 of his money and was left with Rs 30.
So, the amount of money he spent is (2/3) * x. And the amount of money he has left is Rs 30.
Now, we can set up the equation:
x - (2/3)x = 30
To simplify the equation, we can multiply both sides by 3 to get rid of the fraction:
3x - 2x = 90
x = 90
Therefore, the boy had Rs 90 in the beginning.