A drop of volume 10^-10m^3 spreads out on a water to make a circular film of radius 10^-1m. What is the thickness of the film?
the volume of a cylinder is base * height. So, you have
v = πr^2 h
Now plug in your numbers for v and r, and find h.
To find the thickness of the film, we can use the formula:
Volume of the film = Area of the film x Thickness of the film
Given:
Volume of the drop = 10^-10 m^3
Radius of the film = 10^-1 m
First, let's find the area of the film:
Area of the film = πR^2
= π(10^-1)^2
= π(10^-2)
= 0.01π
Now, we can rearrange the formula to solve for the thickness of the film:
Thickness of the film = Volume of the drop / Area of the film
Substituting the values:
Thickness of the film = 10^-10 m^3 / (0.01π)
Calculating the numerical value:
Thickness of the film ≈ 10^-10 m^3 / (0.01 × 3.14159)
≈ 10^-10 m^3 / 0.0314159
≈ 3.18 x 10^-9 m
Therefore, the thickness of the film is approximately 3.18 x 10^-9 meters.