A son is 8 years old. His father is five times as old.

How old was the father when his son was born?

son = 8

father = 5*8 = 40
when son was born, father was 32
In x years, you want
40+x = 2(8+x)
Now solve for x

A son is 8 years old. His father is five times as old.

* How old will the father be when he will be twice as old as his son?

To find out how old the father was when his son was born, we need to determine the son's age at the time of his birth.

Given that the son is currently 8 years old, we can conclude that he was born 8 years ago.

Now, since the father is five times as old as the son, we can calculate the father's age by multiplying the son's age by 5:

Father's age = Son's age * 5 = 8 * 5 = 40

Therefore, the father was 40 years old when his son was born.

To determine how old the father was when his son was born, we need to subtract the son's age from the father's current age. First, let's find out the father's current age.

Given that the son is 8 years old, we can calculate the father's age by multiplying the son's age by 5, as mentioned in the problem statement. Therefore, the father's age would be 8 * 5 = 40 years old.

Now, to determine how old the father was when his son was born, we subtract the son's age from the father's current age.

Father's age when son was born = Father's current age - Son's age
Father's age when son was born = 40 - 8 = 32 years old

Therefore, when the son was born, the father was 32 years old.