How much heat is contained in 100 kg of water at 60.0 °C? (Hint: A substance at absolute zero, -273o C, has 0 heat content.)
To calculate the heat content of a substance, we need to use the formula:
Q = m * c * ΔT
Where:
Q is the heat content (in joules),
m is the mass of the substance (in kilograms),
c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius),
ΔT is the change in temperature (in degrees Celsius).
In this case, we are given:
m = 100 kg (mass of water)
ΔT = 60.0 °C (change in temperature)
The specific heat capacity of water is approximately 4.18 J/g·°C.
To convert the mass from kg to g, multiply it by 1000:
m = 100 kg * 1000 = 100,000 g
Now we can calculate the heat content:
Q = m * c * ΔT
Q = (100,000 g) * (4.18 J/g·°C) * (60.0 °C)
Before calculating, be sure to convert grams to kg:
m = 100,000 g / 1000 = 100 kg
Q = (100 kg) * (4.18 J/g·°C) * (60.0 °C)
Simplifying the equation, we get:
Q = 250,800 J
Therefore, there is 250,800 joules of heat contained in 100 kg of water at 60.0 °C.